top of page
4
C/C++ Program for Lucky Numbers.
program solution
#include <stdio.h>
#define bool int
/* Returns 1 if n is a lucky no. ohterwise returns 0*/
bool isLucky(int n)
{
static int counter = 2;
/*variable next_position is just for readability of the program we can remove it and use n only */
int next_position = n;
if(counter > n)
return 1;
if(n%counter == 0)
return 0;
/*calculate next position of input no*/
next_position -= next_position/counter;
counter++;
return isLucky(next_position);
}
/*Driver function to test above function*/
int main()
{
int x = 5;
if( isLucky(x) )
printf("%d is a lucky no.", x);
else
printf("%d is not a lucky no.", x);
getchar();
}
Output
5 is not a lucky no.
bottom of page